2x^(2/5)+3x^(1/5)+1=0

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Solution for 2x^(2/5)+3x^(1/5)+1=0 equation: 


x in (-oo:+oo)

2*x^(2/5)+3*x^(1/5)+1 = 0

t_1 = x^(1/5)

2*t_1^2+3*t_1^1+1 = 0

2*t_1^2+3*t_1+1 = 0

DELTA = 3^2-(1*2*4)

DELTA = 1

DELTA > 0

t_1 = (1^(1/2)-3)/(2*2) or t_1 = (-1^(1/2)-3)/(2*2)

t_1 = -1/2 or t_1 = -1

t_1 = -1

x^(1/5)+1 = 0

1*x^(1/5) = -1 // : 1

x^(1/5) = -1

( -1 < 0 i 1/5 in (0:1) ) => x naleu017Cy do O

t_1 = -1/2

x^(1/5)+1/2 = 0

1*x^(1/5) = -1/2 // : 1

x^(1/5) = -1/2

( -1/2 < 0 i 1/5 in (0:1) ) => x naleu017Cy do O

x belongs to the empty set

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